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Hi everyone. Can anyone help me on this game I played quite a while ago? Here is a screenshot of the score of that particular hand:

https://picasaweb.google.com/lh/photo/e ... directlink

My hand contains a 556677 iipeiko, but isn't counted by tenhou? Or am I missing something here?

I can't see your photo.. says no access.. but without seeing it.. is your hand open? Because iipeikou only counts when your hand is closed.

Sorry, my mistake. If you can see it now, my hand is in riichi.

Is it actually because it is counted as chiitoi and thus not counted as iipeiko? Is there a rule as to which ones take priority?

Yes if you get chiitoitsu you can't combine it with iipeikou. On the flipside if you get ryanpeikou it cant combine with chiitoitsu. In other words if you get what you got...

this only counts as chiitoitsu

if you got on the other hand for example...

this counts as ryanpeikou and not chiitoitsu.

Hope that helped.

In other words, you get the most valuable one. Chiitoi (2 han) over Iipeikou (1 han), but Ryanpeikou (3 han) over Chiitoi (2 han).

All of that plus: Each tile can be single, in a pair, in a sequence, or in a triplet. No tile can be in both a pair and a sequence. Since your hand's only legal form was seven pairs, you had no sequences. The hand still qualifies for any yaku that considers the whole hand, such as tanyao, juchan, honro, honitsu, chinitsu.