
At first sight, I'll say

Moderator: Shirluban
The hand was 2-shanten before drawing the red 5p, and it will still be 2-shanten no matter what tile we discard. There was nothing 3-shanten about the possible solution I described. You can see for yourself that the only tiles I added to complete the hand are 3s, 4p, and 6p. Therefore, only two tiles were necessary to reach tenpai.Senechal wrote:Totally disagreeing with WaveMaster who produced a 3-shanten solution for a 2-shanten hand.
Ludicrous is the right word!Still find it ludicrous. You're still planning on filling three closed waits to finish your hand.
You're going off on some weird assumption. I was responding to the post directly above mine which claimed that discarding 8s would backfire if you later drew 3s or 4s. This is not the case, as the poster later noted in an edit. If you discard 8s and then draw 3s or 4s, your hand increases from 2-shanten to 1-shanten (by discarding either 4m or 6s). I demonstrated this by showing one possible hand where 8s was discarded, 3s was added, and the hand was completed with only 2 additional tiles (4p and 6p). A discussion about the shanten count of a hand has nothing to do with likelihoods or whether you draw the tiles yourself or not. I showed a complete hand without a drawn tile because I was worried readers might otherwise misunderstand.Senechal wrote:edit: confused Wavemaster's example final result with a hand as it would properly develop. Can you space out a 14th tile or something when you do that ?
Still find it ludicrous. You're still planning on filling three closed waits to finish your hand.
A shanpon wait with a dora pair makes more sense than that. Barely.